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Boyle's Law Calculation: Find Gas Pressure in a 180mL Vessel

A diagram showing gas expansion from a 120mL vessel at 1.2 bar to a 180mL vessel at 0.8 bar, illustrating Boyle's Law.
Visualizing Boyle’s Law: As the volume increases from 120mL to 180mL, the pressure drops from 1.2 bar to 0.8 bar at a constant 35°C.


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 * Ideal Gas Law Overview: "Mastered Boyle's Law? Now see how Temperature fits in with the Ideal Gas Law (PV=nRT)."
 * Chemistry Practice Problems: "Browse our full library of Gas Law Practice Questions for more exam prep."
 * Units of Pressure Conversion: "Confused about Bars vs. Pascals? Check out our Pressure Unit Conversion Guide."


Gas Law Practice Problem

Problem 1: Boyle's Law

A vessel of 120 mL capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at the same temperature. What would be its pressure?

Solution:
Using Boyle's Law: P1V1 = P2V2

1. P1 = 1.2 bar, V1 = 120 mL
2. V2 = 180 mL, P2 = ?
3. P2 = (1.2 × 120) / 180
4. P2 = 0.8 bar
Gas Pressure Calculation - Boyle's Law

Problem: Gas Pressure Calculation

1. Identification of the Physical Process

The problem describes a gas undergoing a change in volume and pressure while the temperature remains constant at 35°C. For a fixed amount of gas at a constant temperature, the relationship between pressure and volume is governed by the Boyle's Law.

2. Given Parameters

The initial and final states of the gas are defined by the following variables:

      Initial pressure (P1): 1.2 bar
      Initial volume (V1): 120 mL
      Final volume (V2): 180 mL
      Temperature (T): 35°C (constant)

3. Mathematical Formulation

According to Boyle's Law, the product of pressure and volume is constant for a given mass of confined gas as long as the temperature is stationary:

P1V1 = P2V2

To find the final pressure (P2), we rearrange the equation:

P2 = (P1V1) / V2

4. Calculation

Substitute the known values into the rearranged expression:

P2 = (1.2 bar × 120 mL) / 180 mL
P2 = 144 bar·mL / 180 mL
P2 = 0.8 bar

The units of volume (mL) cancel out, leaving the final result in the units of pressure (bar).

Final Result: 0.8 bar

-By Dr.Sanjaykumar pawar

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