Boyle's Law Calculation: Find Gas Pressure in a 180mL Vessel
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| Visualizing Boyle’s Law: As the volume increases from 120mL to 180mL, the pressure drops from 1.2 bar to 0.8 bar at a constant 35°C. |
Problem 1: Boyle's Law
A vessel of 120 mL capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at the same temperature. What would be its pressure?
Using Boyle's Law: P1V1 = P2V2
1. P1 = 1.2 bar, V1 = 120 mL
2. V2 = 180 mL, P2 = ?
3. P2 = (1.2 × 120) / 180
4. P2 = 0.8 bar
Problem: Gas Pressure Calculation
1. Identification of the Physical Process
The problem describes a gas undergoing a change in volume and pressure while the temperature remains constant at 35°C. For a fixed amount of gas at a constant temperature, the relationship between pressure and volume is governed by the Boyle's Law.
2. Given Parameters
The initial and final states of the gas are defined by the following variables:
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• Initial pressure (P1): 1.2 bar
•Initial volume (V1): 120 mL
•Final volume (V2): 180 mL
•Temperature (T): 35°C (constant)
3. Mathematical Formulation
According to Boyle's Law, the product of pressure and volume is constant for a given mass of confined gas as long as the temperature is stationary:
To find the final pressure (P2), we rearrange the equation:
4. Calculation
Substitute the known values into the rearranged expression:
P2 = 144 bar·mL / 180 mL
P2 = 0.8 bar
The units of volume (mL) cancel out, leaving the final result in the units of pressure (bar).

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