Very Short Answer Questions with answers (1-mark each) from the Class 10 CBSE Science Chapter "Carbon and its Compounds" — based on the questions you've listed: 1. Name the element whose one of the allotropic forms is buckminsterfullerene. Answer: Carbon. 2. What are the two properties of carbon which lead to the formation of a large number of carbon compounds? Answer: Catenation and tetravalency. **3. State whether the following statement is true or false: “Diamond and graphite are the covalent compounds of carbon element (C).”** Answer: True. 4. Name the scientist who disproved the 'vital force theory' for the formation of organic compounds. Answer: Friedrich Wöhler. 5. Name the element whose allotropic form is graphite. Answer: Carbon. 6. In addition to some propane and ethane, LPG cylinders contain mainly two isomers of another alkane. Name the two isomers and write their condensed structural formulae. Answer: n-butane ...
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Calculate Grams of Sodium Bicarbonate Easily (Step-by-Step)
Calculate Grams of Sodium Bicarbonate | Stoichiometry Solution Problem: How many grams of sodium bicarbonate are required to neutralize 10.0 ml of 0.902 M vinegar? (1) 8.4 g (2) 1.5 g (3) 0.75 g (4) 1.07 g Calculate Grams of Sodium Bicarbonate To determine the mass of sodium bicarbonate (NaHCO₃) required to neutralize vinegar ( acetic acid , CH₃COOH), we use principles of stoichiometry . Step 1: Balanced Chemical Equation This is a neutralization reaction : NaHCO₃ (s) + CH₃COOH (aq) → CH₃COONa (aq) + CO₂ (g) + H₂O (l) The stoichiometric ratio is 1 : 1 . Step 2: Calculate Moles of Acetic Acid Given: Volume (V) = 10.0 mL = 0.0100 L Molarity (M) = 0.902 mol/L n = M × V = 0.902 × 0.0100 = 0.00902 mol Step 3: Moles of Sodium Bicarbonate Since ratio is 1:1: n(NaHCO₃) = 0.00902 mol Step 4: Calculate Mass Molar Mass of NaHCO₃: Na = 22.99 g/mol H = 1.01 g/mol C = 12.01 g/mol O...
2.Carbon and Its Compounds chapter):
Very Short Answer Type Questions (VSATQs) with answers, suitable for Class 10 CBSE Chemistry (based on Carbon and Its Compounds chapter): 1. Write the molecular formula of ethanol. Answer: C₂H₅OH 2. What is the next higher homologue of methanol (CH₃OH)? Answer: Ethanol (C₂H₅OH) 3. Identify the functional group present in the following compound and name it according to IUPAC system: CH₃OH Answer: Functional group –OH (Hydroxyl group); IUPAC name: Methanol 4. Give the common name and IUPAC name of the simplest aldehyde. Answer: Common name: Formaldehyde IUPAC name: Methanal 5. What is the common name of methanal? Answer: Formaldehyde 6. Write the names of the following functional groups: (a) –C≡C– → Alkyne (b) –CO– (carbonyl group between two alkyl groups) → Ketone 7. Name the simplest ketone. Answer: Propanone (also known as acetone) 8. What is the common name of propanone? Answer: Acetone 9. Write the IUPAC names of the following: (i) CH₃COC...
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