Calculate Grams of Sodium Bicarbonate Easily (Step-by-Step)
Calculate Grams of Sodium Bicarbonate | Stoichiometry Solution Problem: How many grams of sodium bicarbonate are required to neutralize 10.0 ml of 0.902 M vinegar? (1) 8.4 g (2) 1.5 g (3) 0.75 g (4) 1.07 g Calculate Grams of Sodium Bicarbonate To determine the mass of sodium bicarbonate (NaHCO₃) required to neutralize vinegar ( acetic acid , CH₃COOH), we use principles of stoichiometry . Step 1: Balanced Chemical Equation This is a neutralization reaction : NaHCO₃ (s) + CH₃COOH (aq) → CH₃COONa (aq) + CO₂ (g) + H₂O (l) The stoichiometric ratio is 1 : 1 . Step 2: Calculate Moles of Acetic Acid Given: Volume (V) = 10.0 mL = 0.0100 L Molarity (M) = 0.902 mol/L n = M × V = 0.902 × 0.0100 = 0.00902 mol Step 3: Moles of Sodium Bicarbonate Since ratio is 1:1: n(NaHCO₃) = 0.00902 mol Step 4: Calculate Mass Molar Mass of NaHCO₃: Na = 22.99 g/mol H = 1.01 g/mol C = 12.01 g/mol O...
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